25c^3-4c=0

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Solution for 25c^3-4c=0 equation:


Simplifying
25c3 + -4c = 0

Reorder the terms:
-4c + 25c3 = 0

Solving
-4c + 25c3 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), 'c'.
c(-4 + 25c2) = 0

Factor a difference between two squares.
c((2 + 5c)(-2 + 5c)) = 0

Subproblem 1

Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0

Subproblem 2

Set the factor '(2 + 5c)' equal to zero and attempt to solve: Simplifying 2 + 5c = 0 Solving 2 + 5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 5c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 5c = 0 + -2 5c = 0 + -2 Combine like terms: 0 + -2 = -2 5c = -2 Divide each side by '5'. c = -0.4 Simplifying c = -0.4

Subproblem 3

Set the factor '(-2 + 5c)' equal to zero and attempt to solve: Simplifying -2 + 5c = 0 Solving -2 + 5c = 0 Move all terms containing c to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + 5c = 0 + 2 Combine like terms: -2 + 2 = 0 0 + 5c = 0 + 2 5c = 0 + 2 Combine like terms: 0 + 2 = 2 5c = 2 Divide each side by '5'. c = 0.4 Simplifying c = 0.4

Solution

c = {0, -0.4, 0.4}

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